document.write( "Question 99620: How do I solve for t (time ) in the following equation. This is from a college physics book\r
\n" ); document.write( "\n" ); document.write( "y = initial velocity x time + 1/2 (acceleration) time ^2\r
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\n" ); document.write( "\n" ); document.write( "-1.69 m = (1094 m/s )t + 1/2 ( -9.8 m/s^2 ) t ^2
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Algebra.Com's Answer #72479 by Adam(64)\"\" \"About 
You can put this solution on YOUR website!
Is is a standard quadratic eaquation of \"ax%5E2%2Bbx%2Bc=0\" , and can be solved with formula with coefficients: \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" I'll use my favourite notation :-),let's denote s for distance, t - time,a - acceleration,v0-initial velocity. then we have \"s+=+%281%2F2%29at%5E2%2Bv0t\"
\n" ); document.write( "\"%281%2F2%29at%5E2%2Bv0t-s=0\" substituting into formula we get \"x+=+%28-v0+%2B-+sqrt%28+v0%5E2-2%2Aa%2As+%29%29%2F%28a%29+\" with values we get - getting two answers - -0.0015 and 223.2669 we can forget the negative one because it is phsically imposibble (time can never be negative) - btw those numbers in your equation seem really suspicious to me negative distance....that's either new theory of spacetime or....
\n" ); document.write( "anyway quick rememberance:\r
\n" ); document.write( "\n" ); document.write( "s...distance[m],distance you travelled
\n" ); document.write( "v...velocity[m/s],change of s during infinitesimal change of t ds/dt to be precise
\n" ); document.write( "a...acceleration[m/s^2],dv/dt\r
\n" ); document.write( "\n" ); document.write( "How to have something from nothing...
\n" ); document.write( "now, what I want to show is not fully rigorous, but it is a lot of fun :-),
\n" ); document.write( "let's start with a = a with help of our formulae we can state that v=S[t]dt (primitive function) thus v = a*t+c now after deep thought we may state that constant will probably be v0, so v = a*t+v0, followed by s= V[t]dt
\n" ); document.write( "s = 1/2a*t^2+v0*t+s0 (thought), now you try to make similiar conclusions, starting with a = 0. Good luck :-D \r
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