document.write( "Question 99598: i did this problem but i dunno if it is correct can you please check it for me\r
\n" ); document.write( "\n" ); document.write( "12xy^3-4x^2y^2=\r
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\n" ); document.write( "\n" ); document.write( "4xy.3y-4xy^2.2=0
\n" ); document.write( "4xy^2(3y-N)=0
\n" ); document.write( "4xy^2=0
\n" ); document.write( "xy^2=01y\r
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\n" ); document.write( "\n" ); document.write( "xy=0 and y=0 3y=x
\n" ); document.write( " y=x
\n" ); document.write( " =3 \r
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Algebra.Com's Answer #72472 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
12xy^3-4x^2y^2
\n" ); document.write( "= 4xy^2(3y - x)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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