document.write( "Question 99598: i did this problem but i dunno if it is correct can you please check it for me\r
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document.write( "12xy^3-4x^2y^2=\r
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document.write( "4xy.3y-4xy^2.2=0
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document.write( "4xy^2(3y-N)=0
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document.write( "4xy^2=0
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document.write( "xy^2=01y\r
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document.write( "xy=0 and y=0 3y=x
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document.write( " y=x
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document.write( " =3 \r
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Algebra.Com's Answer #72472 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 12xy^3-4x^2y^2 \n" ); document.write( "= 4xy^2(3y - x) \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |