document.write( "Question 1109670: The number of terms in an A.P. whose first term is 5, common difference 3, and sum 55 is \n" ); document.write( "
Algebra.Com's Answer #724643 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! the formula for the sum of the first n terms of a arithmetic progression(AP) when we do not know the nth term is \n" ); document.write( ": \n" ); document.write( "s(n) = (n/2) * (2 * a(0) + (n-1) * d), where a(0) is the first term and d is the common difference \n" ); document.write( ": \n" ); document.write( "we are given \n" ); document.write( ": \n" ); document.write( "(1) 55 = (n/2) * (2*5 + 3*(n-1)) \n" ); document.write( ": \n" ); document.write( "solve for n \n" ); document.write( ": \n" ); document.write( "55 = (n/2) * (10 + 3n - 3) \n" ); document.write( ": \n" ); document.write( "110 = n * (7 + 3n) \n" ); document.write( ": \n" ); document.write( "3n^2 +7n -110 = 0 \n" ); document.write( ": \n" ); document.write( "(3n+22) * (n-5) = 0 \n" ); document.write( ": \n" ); document.write( "n = -22/7 and n = 5 \n" ); document.write( ": \n" ); document.write( "we reject the negative value for n \n" ); document.write( ": \n" ); document.write( "**************************************** \n" ); document.write( "there are 5 terms, namely \n" ); document.write( ": \n" ); document.write( "5, 8, 11, 14 , 17 \n" ); document.write( ": \n" ); document.write( "to check this we use the formula \n" ); document.write( ": \n" ); document.write( "55 = (5/2) * (2 * 5 + 3 * (5 - 1) \n" ); document.write( ": \n" ); document.write( "55 = (5/2) * 22 = 55 \n" ); document.write( ": \n" ); document.write( "our answer checks \n" ); document.write( "***************************************** \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |