document.write( "Question 99604: Solve the system of equations using the elimination method. \r
\n" ); document.write( "\n" ); document.write( "2a + 3b = -1 \r
\n" ); document.write( "\n" ); document.write( "3a + 5b = -2
\n" ); document.write( "

Algebra.Com's Answer #72459 by elima(1433)\"\" \"About 
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With the elimination method, we want to eliminate one of the variables;
\n" ); document.write( "2a + 3b = -1
\n" ); document.write( "3a + 5b = -2
\n" ); document.write( "We will multiply the first equation with -3 and the second with 2, so we can eliminate the a;
\n" ); document.write( "-3(2a+3b=-1)
\n" ); document.write( "2(3a+5b=-2)
\n" ); document.write( "new equations;
\n" ); document.write( "-6a-9b=3
\n" ); document.write( "6a+10b=-4
\n" ); document.write( "Add the two equations together, and you can eliminate the a;
\n" ); document.write( "b=-1
\n" ); document.write( "Now plug the -1 into one of the original equations;
\n" ); document.write( "2a+3(-1)=-1
\n" ); document.write( "2a-3=-1
\n" ); document.write( "2a=2
\n" ); document.write( "a=1
\n" ); document.write( ":)\r
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