document.write( "Question 1109607: Suppose that the manufacturer of a DVD player has found that, when the unit price is p dollars, the revenue R (in dollars) as a function of the price p is
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document.write( "R(p)=-2.5p^2+850p
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document.write( " (a) For what price will the revenue be maximized?
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document.write( "(b) What is the maximum revenue? \n" );
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Algebra.Com's Answer #724589 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! R=-2.5p^2+850 p \n" ); document.write( "This is a quadratic where the vertex is the maximum value. \n" ); document.write( "vertex p value is -b/2a=-850/-2.5*2=+170 so $170 is price at maximum revenue \n" ); document.write( "R=-2.5*170^2+850*170 \n" ); document.write( "=-72250+144500 \n" ); document.write( "=$72,250 \n" ); document.write( " |