document.write( "Question 1109607: Suppose that the manufacturer of a DVD player has found​ that, when the unit price is p​ dollars, the revenue R​ (in dollars) as a function of the price p is
\n" ); document.write( "R(p)=-2.5p^2+850p
\n" ); document.write( " ​(a) For what price will the revenue be​ maximized?
\n" ); document.write( "​(b) What is the maximum​ revenue?
\n" ); document.write( "

Algebra.Com's Answer #724589 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
R=-2.5p^2+850 p
\n" ); document.write( "This is a quadratic where the vertex is the maximum value.
\n" ); document.write( "vertex p value is -b/2a=-850/-2.5*2=+170 so $170 is price at maximum revenue
\n" ); document.write( "R=-2.5*170^2+850*170
\n" ); document.write( "=-72250+144500
\n" ); document.write( "=$72,250
\n" ); document.write( "\"graph%28300%2C300%2C-60%2C200%2C-100000%2C100000%2C-2.5x%5E2%2B850x%29\"
\n" ); document.write( "
\n" );