document.write( "Question 1109610: An airplane encountered a head wind during a flight between Joppetown and Jawsburgh which took 5 hours and 24 minutes. The return flight took 5 hours. If the distance from Joppetown to Jawsburgh is 2700 ​miles, find the airspeed of the plane​ (the speed of the plane in still​ air) and the speed of the​ wind, assuming both remain constant. \n" ); document.write( "
Algebra.Com's Answer #724587 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
velocity * time=distance
\n" ); document.write( "V (going)*5.4 hours=2700 miles, so V (going)=500 mph.
\n" ); document.write( "V(return)*5 hours=2700 miles, so V(return)=540 mph
\n" ); document.write( "velocity=p-w with headwind, p plane, w wind
\n" ); document.write( "p+w with tail wind
\n" ); document.write( "p+w=540
\n" ); document.write( "p-w=500, add them
\n" ); document.write( "2p=1040
\n" ); document.write( "p=520 mph plane
\n" ); document.write( "w=20 mph wind
\n" ); document.write( "
\n" );