document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1109565>Question 1109565</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A family drove from home to Truckee at 55 mph and returned the same route at 40 mph due to a snowstorm.  The total travel time was 4.75 hours.  Determine the distance between their home and Truckee </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #724550 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=724550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is another way you can solve this problem.  If you are good with mental arithmetic, it is much faster than the algebraic solution shown by the other tutor.<br><BR>\n" );
document.write( "This alternate method is based on the fact that, since the distances are the same, the ratio of the speeds is the reciprocal of the ratio of the times.<br><BR>\n" );
document.write( "The ratio of the two speeds is 55:40 = 11:8; so the ratio of times is 8:11.<br><BR>\n" );
document.write( "4.75 hours is 19/4 hours; 19/4 divided in the ratio 8:11 is 8/4=2 hours and 11/4 hours.<br><BR>\n" );
document.write( "Then the driving distance can be found using the time and rate for the trip in either direction:<BR>\n" );
document.write( "55 mph times 2 hours = 110 miles<BR>\n" );
document.write( "40 mph times 11/4 hours = 110 miles </SPAN>\n" );
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