document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1109560>Question 1109560</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Sally is traveling 65 mph and Mark is traveling 50 mph. how long will it take Mark to catch up is Sally had a two hour Head start  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #724549 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=724549\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br>Obviously you have misstated the problem.  If Sally has a 2 hour head start and is traveling faster than Mark, then Mark will never catch up.<br><BR>\n" );
document.write( "So assuming Sally has the 2 hour head start and Mark has the higher speed, then we can solve the problem.<br><BR>\n" );
document.write( "Sally has a 2 hour head start, traveling at 50 mph; in those 2 hours she has traveled 2*50 = 100 miles.  So her head start is 100 miles.<br><BR>\n" );
document.write( "Mark is catching up to Sally at a rate of (65-50) = 15 mph.<br><BR>\n" );
document.write( "The time required for Mark to catch up to Sally is then 100/15 hours, or 6 2/3 hours, or 6 hours and 40 minutes.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );