document.write( "Question 98109: 5x/7-2x/5=6/35 These are fractions 5x, 2x, 6 are all the numerator... \n" ); document.write( "
Algebra.Com's Answer #72448 by timmy1729(23)\"\" \"About 
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\"%285x%29%2F7-%282x%29%2F5+=+6%2F35\" To solve this, multiply by \"5%2F5\" in the first fraction and \"7%2F7\" in the second. That makes:
\n" ); document.write( "\"%2825x%29%2F35-%2814x%29%2F35+=+6%2F35\"
\n" ); document.write( "Now multiply both sides by 35 to get rid of the fractions.
\n" ); document.write( "\"25x+-+14x+=+6\"\r
\n" ); document.write( "\n" ); document.write( "That gives us \"11x+=+6\" and \"x+=+6%2F11\"
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