document.write( "Question 1109469: At what distance from a source of light will the intensity of illumination be half as great as it is at a distance of 6 inches \n" ); document.write( "
Algebra.Com's Answer #724472 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! At what distance from a source of light will the intensity of illumination be half as great as it is at a distance of 6 inches \n" ); document.write( "------ \n" ); document.write( "I = k/d^2 --- k = a constant. \n" ); document.write( "d^2 = k/I \n" ); document.write( "----------- \n" ); document.write( "d^2 = (k/(I/2)) = 2k/I \n" ); document.write( "d = 6*sqrt(2) inches \n" ); document.write( "---------------------------------------- \n" ); document.write( "That might be confusing. \n" ); document.write( "--- \n" ); document.write( "Illumination intensity is a function of the inverse of the square of the distance. \n" ); document.write( "d*2 = I/4 \n" ); document.write( "d*3 = I/9 \n" ); document.write( "d*x = I/x^2 --> d*sqrt(x) = I/x \n" ); document.write( "----------------- \n" ); document.write( "Inverse of the square of distance is common: \n" ); document.write( "gravity, magnetism, E-field (of a point), sound intensity, and others.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |