document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1109484>Question 1109484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Working together, two pumps can drain a certain pool in 4 <BR>\n" );
document.write( " hours. If it takes the older pump 12<BR>\n" );
document.write( " hours to drain the pool by itself, how long will it take the newer pump to drain the pool on its own?<BR>\n" );
document.write( "Do not do any rounding.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #724462 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=724462\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the time it takes the newer pump to drain the pool<BR>\n" );
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document.write( "(1/12) + (1/x) = 1/4<BR>\n" );
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document.write( "1 + 12/x = 3<BR>\n" );
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document.write( "12/x = 2/1<BR>\n" );
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document.write( "2x = 12<BR>\n" );
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document.write( "x = 6<BR>\n" );
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document.write( "it takes the newer pump 6 hours to drain the pool on its own<BR>\n" );
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