document.write( "Question 1109378: Person A takes 6 days less than the time taken by the person B to finish a piece of work. If both A and B together can finish it in 4 days. Find the time that B would take to finish this work by himself. \n" ); document.write( "
Algebra.Com's Answer #724368 by stanbon(75887)\"\" \"About 
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Person A takes 6 days less than the time taken by the person B to finish a piece of work. If both A and B together can finish it in 4 days. Find the time that B would take to finish this work by himself.
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\n" ); document.write( "B DATA:
\n" ); document.write( "time = x day/job ; rate = 1/x job/day
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\n" ); document.write( "A DATA:
\n" ); document.write( "time = x-6 days/job ; rate = 1/(x-6) job/day
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\n" ); document.write( "Together DATA:
\n" ); document.write( "time = 4 days/job ; rate = 1/4 job/day
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\n" ); document.write( "Equation:
\n" ); document.write( "rate + rate = together rate
\n" ); document.write( "1/x + 1/(x-6) = 1/4
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\n" ); document.write( "4(x-6) + 4x = x(x-6)
\n" ); document.write( "8x-24 = x^2 - 6x
\n" ); document.write( "x^2 - 14x + 24 = 0
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\n" ); document.write( "x = [14 +-sqrt(14^2 - 4*1*24)]/2
\n" ); document.write( "x = 12 days (time for \"A\" to do the job)
\n" ); document.write( "x-6 = 6 days (time for B to do the job alone)
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