document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1109388>Question 1109388</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The base and height of a triangle are (x+3)cm and (2x-5)cm respectively.If the area of the triangle is 20cm squared ,find x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #724364 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=724364\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The base and height of a triangle are (x+3)cm and (2x-5)cm respectively.If the area of the triangle is 20cm squared ,find x <BR>\n" );
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document.write( "Area = (1/2)(base)(height)<BR>\n" );
document.write( "20 = (1/2)(x+3)(2x-5)<BR>\n" );
document.write( "40 = 2x^2 +x - 15<BR>\n" );
document.write( "2x^2 + x - 55 = 0<BR>\n" );
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document.write( "x = [-1 +- sqrt(1-4*2*(-55))]/4<BR>\n" );
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document.write( "x = [-1 +- sqrt(520)]/4<BR>\n" );
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document.write( "x = 20/4 = 5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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