document.write( "Question 1109379: Explicit formula the sequence & 12th term. \r
\n" ); document.write( "\n" ); document.write( "2, 6, 12, 20\r
\n" ); document.write( "\n" ); document.write( "Am I correct in having the formula be A(n)=n(n+1)? \r
\n" ); document.write( "\n" ); document.write( "This would make t he 12th term 156, right? \r
\n" ); document.write( "\n" ); document.write( "Thanks
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Algebra.Com's Answer #724359 by rothauserc(4718)\"\" \"About 
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2, 6, 12, 20
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\n" ); document.write( "first level differences are
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\n" ); document.write( "4, 6, 8
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\n" ); document.write( "second level differences are
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\n" ); document.write( "2, 2
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\n" ); document.write( "therefore we know the formula is a quadratic of the form
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\n" ); document.write( "an^2 +bn + c
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\n" ); document.write( "for n=1, we have a +b +c = 2
\n" ); document.write( "for n=2, we have 4a +2b +c = 6
\n" ); document.write( "for n=3, we have 9a +3b +c = 12
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\n" ); document.write( "we have a system of three equations in three unknowns
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\n" ); document.write( "subtract the first equation from the second and third equations
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\n" ); document.write( "3a +b = 4
\n" ); document.write( "8a +2b = 10
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\n" ); document.write( "using the first one, solve for b and substitute in the second one
\n" ); document.write( "b = 4-3a
\n" ); document.write( "8a +2(4-3a) = 10
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\n" ); document.write( "8a +8 -6a = 10
\n" ); document.write( "2a = 2
\n" ); document.write( "a = 1
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\n" ); document.write( "substitute for a in 3a +b = 4
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\n" ); document.write( "3(1) + b = 4
\n" ); document.write( "b = 1
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\n" ); document.write( "a = 1 and b = 1, therefore
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\n" ); document.write( "c = 0
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\n" ); document.write( "our formula is n^2 +n
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\n" ); document.write( "x(12) = 12^2 + 12 = 156
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\n" ); document.write( "you are correct
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