document.write( "Question 1109367: As a weather balloon is inflated, its radius increases at the rate of 4 cm per second. Express the volume of the balloon as a function of time, and determine the volume of the balloon after 4 seconds. \n" ); document.write( "
Algebra.Com's Answer #724355 by Alan3354(69443)\"\" \"About 
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As a weather balloon is inflated, its radius increases at the rate of 4 cm per second. Express the volume of the balloon as a function of time, and determine the volume of the balloon after 4 seconds.
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\n" ); document.write( "\"V+=+4pi%2Ar%5E3%2F3\"
\n" ); document.write( "dV/dt = 4pi*r^2*dr/dt --- 1st derivative
\n" ); document.write( "dV/dt = 16pi*r^2 cc/sec
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\n" ); document.write( "If you mean 4 seconds after its volume was zero:
\n" ); document.write( "\"V+=+4pi%2Ar%5E3%2F3+=+4pi%2A16%5E3%2F3\"
\n" ); document.write( "= 16384*pi/3 cc\r
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