document.write( "Question 1109273: I need help. Can't solve it.\r
\n" ); document.write( "\n" ); document.write( "3.25(48x+x(x/6)+2x*sqrt((x/2)^2+(x/6)^2))=50000\r
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Algebra.Com's Answer #724270 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
I need help. Can't solve it.\r
\n" ); document.write( "\n" ); document.write( "3.25(48x+x(x/6)+2x*sqrt((x/2)^2+(x/6)^2))=50000
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\n" ); document.write( "It's just a matter of being careful.\r
\n" ); document.write( "\n" ); document.write( "13(48x+x(x/6)+2x*sqrt((x/2)^2+(x/6)^2)) = 200000
\n" ); document.write( "48x+x(x/6)+2x*sqrt((x/2)^2+(x/6)^2) = 200000/13
\n" ); document.write( "48x + x^2/6 + 2x*sqrt((x^2/4 + (x^2/36)) = 200000/13
\n" ); document.write( "48x + x^2/6 + 2x*sqrt((10x^2/36)) = 200000/13
\n" ); document.write( "48x + x^2/6 + 2x*(x/6)sqrt(10) = 200000/13
\n" ); document.write( "48x + x^2/6 + (x^2/3)sqrt(10) = 200000/13
\n" ); document.write( "x^2/6 + (2x^2/6)sqrt(10) + 48x = 200000/13
\n" ); document.write( "x^2*(2sqrt(10)+1)/6 + 48x - 200000/13 = 0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1.22075922005613x%5E2%2B48x%2B-15384.6153846154+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2848%29%5E2-4%2A1.22075922005613%2A-15384.6153846154=77427.6443111465\".
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\n" ); document.write( " Discriminant d=77427.6443111465 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-48%2B-sqrt%28+77427.6443111465+%29%29%2F2%5Ca\".
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\n" ); document.write( " Quadratic expression \"1.22075922005613x%5E2%2B48x%2B-15384.6153846154\" can be factored:
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\n" ); document.write( " Again, the answer is: 94.3094384866179, -133.629231621412.\n" ); document.write( "Here's your graph:
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