document.write( "Question 1109169: A container contained 500mL of a solution that was 52% water. How much water should be removed from the solution so that the remainder would be only 40% water? \n" ); document.write( "

Algebra.Com's Answer #724226 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "Tutor addingup worked the wrong problem; he added more of the other ingredient to make the solution 40% water.

\n" ); document.write( "Tutor teachmath gave his usual useless response -- a right answer with no work shown. That's a strange way of \"teaching\" math.

\n" ); document.write( "Tutor teachmath: if you are by chance reading this, please stop providing useless answers to people who are nearly always interested in learning HOW to solve a problem -- not just in seeing the answer.

\n" ); document.write( "The other tutor provided a valid solution to the problem.

\n" ); document.write( "My approach would be slightly different:

\n" ); document.write( "The 500mL is 52% water, so it is 48% of the other ingredient.
\n" ); document.write( "48% of 500mL is 240mL.
\n" ); document.write( "If the final solution is to be only 40% water, it must be 60% of the other ingredient.
\n" ); document.write( "If 60% of the final mixture is the original 240mL of the other ingredient, then the volume of the final mixture is 240/.60 = 400mL.
\n" ); document.write( "So, since the original mixture was 500mL, 100mL of water needs to be removed. \n" ); document.write( "

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