document.write( "Question 1109169: A container contained 500mL of a solution that was 52% water. How much water should be removed from the solution so that the remainder would be only 40% water? \n" ); document.write( "
Algebra.Com's Answer #724203 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
48% is not water, at the start.
\n" ); document.write( "60% would be not water , at the end.\r
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\n" ); document.write( "\n" ); document.write( "\"%280.48%2A500%29%2F%28500-x%29=0.6\", for removing x mL of water.\r
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\n" ); document.write( "\n" ); document.write( "\"0.48%2A500=0.6%28500-x%29\"\r
\n" ); document.write( "\n" ); document.write( "\"0.48%2A500%2F0.6=-x%2B500\"\r
\n" ); document.write( "\n" ); document.write( "\"400=-x%2B500\"\r
\n" ); document.write( "\n" ); document.write( "\"x=500-400\"\r
\n" ); document.write( "\n" ); document.write( "\"x=100\"
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