document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1109148>Question 1109148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two coffee jugs, A and B are filled as shown below.<BR>\n" );
document.write( "Jug A:5 cups of water,<BR>\n" );
document.write( "5 teaspoons coffee,<BR>\n" );
document.write( "3 teaspoons sugar.<BR>\n" );
document.write( "Jug B: 3 cups water,<BR>\n" );
document.write( "3 teaspoons coffee,<BR>\n" );
document.write( "2 teaspoons sugar.<BR>\n" );
document.write( "Which jug contains the sweeter coffee? Explain your reasoning.\r<BR>\n" );
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document.write( "My working concluded that jug B is the sweeter coffee, i got stuck in the reasoning \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #724157 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=724157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A: 5:5:3<BR>\n" );
document.write( "B: 3:3:2<BR>\n" );
document.write( "Jug B contains a higher ratio of sugar to coffee and water (2/3, 2/3) vs. Jug a, which contains a lower ratio of sugar to coffee and water (3/5, 3/5)<BR>\n" );
document.write( "Note:<BR>\n" );
document.write( "2/3 is more than 3/5. How much more? This much:<BR>\n" );
document.write( "set both numbers over a common denominator:<BR>\n" );
document.write( "2/3 and 3/5 become 10/15 and 9/15 Now subtract: 10/15-9/15 = 1/15 <BR>\n" );
document.write( "Jug B has 1/15 more sugar than jug A<BR>\n" );
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