document.write( "Question 1109083: Can someone help with this. \r
\n" ); document.write( "\n" ); document.write( "the resistance in a cable conducting electricity varies directly as the length of the cable and inversely as the square of the diameter of the cable. If a cable 8 feet long with a 1-inch diameter has a resistance of 8 ohms, what is the resistance in a cable 20 ft with a diamter of .5 inches \n" ); document.write( "
Algebra.Com's Answer #724095 by stanbon(75887)\"\" \"About 
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the resistance in a cable conducting electricity varies directly as the length of the cable and inversely as the square of the diameter of the cable. If a cable 8 feet long with a 1-inch diameter has a resistance of 8 ohms, what is the resistance in a cable 20 ft with a diameter of .5 inches
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\n" ); document.write( "R = k*L/d^2
\n" ); document.write( "Solve for \"k\"::
\n" ); document.write( "8 = k*8/1^2
\n" ); document.write( "k = 64
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\n" ); document.write( "R = 64*L/d^2
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\n" ); document.write( "R = 64*20/(0.5)^2 = 64*20/(1/4) = 64*80 = 5120 ohms
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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