document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1109070>Question 1109070</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For my homework, I need step by step instructions.\r<BR>\n" );
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document.write( "Point slope form for this problem (-2,1); m=-2 \r<BR>\n" );
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document.write( "Next problems:\r<BR>\n" );
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document.write( "Write the equation for: What number should be added to -64 to get -70.\r<BR>\n" );
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document.write( "Write the equation for: -64 times a number minus 70 is equal to -14 less than the number.\r<BR>\n" );
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document.write( "If the formula for the circumference of a circle is: C=2PIr, r(radius) would equal= (Show work to get \"r\" alone):\r<BR>\n" );
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document.write( "Solve for \"x\" in the inequality:   -3(2x-5)< 3 (x-1)\r<BR>\n" );
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document.write( "Thank you so much for your help!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #724086 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=724086\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Point slope form for this problem (-2,1); m=-2<BR>\n" );
document.write( "The point/slope form y - y1 = m(x-x1)<BR>\n" );
document.write( "in this problem<BR>\n" );
document.write( "x1=-2; y1=1; m=-2<BR>\n" );
document.write( "y - 1 = -2(x-(-2))<BR>\n" );
document.write( "y - 1 =-2(x+2)<BR>\n" );
document.write( ":   <BR>\n" );
document.write( " Write the equation for: What number should be added to -64 to get -70.<BR>\n" );
document.write( "x - 64 = -70 <BR>\n" );
document.write( " Write the equation for: -64 times a number minus 70 is equal to -14 less than the number.<BR>\n" );
document.write( "-64x - 70 = x - 14<BR>\n" );
document.write( ": <BR>\n" );
document.write( " If the formula for the circumference of a circle is: C=2PIr, r(radius) would equal= (Show work to get \"r\" alone): <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Api%2Ar+=+C ALIGN=MIDDLE  ALT=\"2%2Api%2Ar+=+C\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "divide both sides by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Api ALIGN=MIDDLE  ALT=\"2%2Api\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+C%2F%282%2Api%29 ALIGN=MIDDLE  ALT=\"r+=+C%2F%282%2Api%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( " Solve for \"x\" in the inequality: <BR>\n" );
document.write( "-3(2x-5)< 3 (x-1)<BR>\n" );
document.write( "distribute the 3<BR>\n" );
document.write( "-6x + 15 < 3x - 3<BR>\n" );
document.write( "subtract 3x from both sides<BR>\n" );
document.write( "-6x - 3x + 15 = -3<BR>\n" );
document.write( "-9x + 15 < -3<BR>\n" );
document.write( "subtract 15 from both side<BR>\n" );
document.write( "-9x < -3 - 15<BR>\n" );
document.write( "-9x < -18<BR>\n" );
document.write( "get rid of the neg, multiply by -1, this reverses the inequality sign<BR>\n" );
document.write( "9x > 18<BR>\n" );
document.write( "x > 18/9<BR>\n" );
document.write( "x > 2<BR>\n" );
document.write( "You can check the solution in the original equation, replace x with a number greater than 2<BR>\n" );
document.write( "See if it is true  </SPAN>\n" );
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