document.write( "Question 1109046: After 200 throws, a coin has shown head exactly 110 times. By forming an equation and solving it, find how many further consecutive times must a head be thrown for heads to show exactly 70% of the total number of throws. \n" ); document.write( "
Algebra.Com's Answer #724071 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"x\"= number of further consecutive heads leading to \"%2270%25%22\" heads.
\n" ); document.write( "Once those \"x\" further throws showing heads are done,
\n" ); document.write( "the total number of throws will be \"200%2Bx\" :
\n" ); document.write( "the total number of heads will be \"110%2Bx\" ,
\n" ); document.write( "and the ratio of heads to total throws will be
\n" ); document.write( "\"%2270%25%22=70%2F100=0.7\" .
\n" ); document.write( "Then,
\n" ); document.write( "\"%28110%2Bx%29%2F%28200%2Bx%29=0.7\"
\n" ); document.write( "\"110%2Bx=0.7%28200%2Bx%29\"
\n" ); document.write( "\"110%2Bx=140%2B0.7x\"
\n" ); document.write( "\"x-0.7x=140-110\"
\n" ); document.write( "\"0.3x=30\"
\n" ); document.write( "\"x=30%2F0.3\"
\n" ); document.write( "\"x=highlight%28100%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" );