document.write( "Question 1109022: Margaret drove to a business appointment at 80 mph. Her average speed on the return trip was 70 mph. The return trip took 1/7hr longer because of heavy traffic. How far did she travel to the​ appointment? \n" ); document.write( "
Algebra.Com's Answer #724038 by josmiceli(19441)\"\" \"About 
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Let \"+d+\" = the one-way distance
\n" ); document.write( "Let \"+t+\" = time in hrs for the trip at \"+80+\" mi/hr
\n" ); document.write( "(1) \"+d+=+80t+\"
\n" ); document.write( "(2) \"+d+=+70%2A%28+t+%2B+1%2F7+%29+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "\"+80t+=+70%2A%28+t+%2B+1%2F7+%29+\"
\n" ); document.write( "\"+80t+=+70t+%2B+10+\"
\n" ); document.write( "\"+10t+=+10+\"
\n" ); document.write( "\"+t+=+1+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+d+=+80%2A1+\"
\n" ); document.write( "The appointment was 80 mi away
\n" ); document.write( "----------------------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+d+=+70%2A%28+1+%2B+1%2F7+%29+\"
\n" ); document.write( "(2) \"+d+=+70%2A%28+8%2F7+%29+\"
\n" ); document.write( "(2) \"+d+=+80+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" ); document.write( "
\n" );