document.write( "Question 1108965: The annual interest on a $19,000 investment exceeds the interest earned on a $5000 investment by $617. The $19,000 is invested at a 0.3% higher rate of interest than the $5000. What is the interest rate of each investment? \n" ); document.write( "
Algebra.Com's Answer #724012 by josmiceli(19441)\"\" \"About 
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This is a simple interest problem
\n" ); document.write( "Use \"+I+=+P%2Ar%2At+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "(1) \"+I+%2B+617+=+19000%2A%28+r+%2B+.003+%29%2A1+\"
\n" ); document.write( "(2) \"+I++=+5000%2Ar%2A1+\"
\n" ); document.write( "----------------------------------
\n" ); document.write( "Plug (2) into (1)
\n" ); document.write( "(1) \"+5000r+%2B+617+=+19000r+%2B+57+\"
\n" ); document.write( "(1) \"+14000r+=+560+\"
\n" ); document.write( "(1) \"+r+=+.04+\"
\n" ); document.write( "and
\n" ); document.write( "\"+r+%2B+.003+=+.043+\"
\n" ); document.write( "------------------------
\n" ); document.write( "The rate for $19,000 investment is 4.3%
\n" ); document.write( "The rate for $5,000 investment is 4%
\n" ); document.write( "----------------------------------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+I+%2B+617+=+19000%2A.043+\"
\n" ); document.write( "(1) \"+I+=+817+-+617+\"
\n" ); document.write( "(1) \"+I+=+200+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+I+=+5000%2A.04+\"
\n" ); document.write( "(2) \"+I+=+200+\"
\n" ); document.write( "OK
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