document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1108986>Question 1108986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ratio of x to y is 4:9 and the ratio of y to z is 18:15, what is the ratio of x to z? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #724001 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=724001\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "While the algebraic method shown by the other tutor is perfectly good, I find it a bit confusing to do it that way, finding it easy to get the wrong numbers in the wrong places.<br><BR>\n" );
document.write( "Here is how I like to do problems like this....<br><BR>\n" );
document.write( "Since we are given the ratio of x to y and the ratio of y to z, if we can change one or both of the given ratios to equivalent ratios such that the y value is the same in both, then we can easily find the ratio of x to z.<br><BR>\n" );
document.write( "Since the y value in the first ratio is 9 and it is 18 in the second ratio, we can double both numbers in the first ratio to make y equal to 18 in both ratios.  Then the compound ratio will show us the ratio between x and z.<br><BR>\n" );
document.write( "x:y = 4:9 = 8:18<BR>\n" );
document.write( "y:z = 18:15<br><BR>\n" );
document.write( "Therefore<BR>\n" );
document.write( "x:y:z = 8:18:15<br><BR>\n" );
document.write( "So<BR>\n" );
document.write( "x:z = 8:15 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );