document.write( "Question 1108892: water is 20% the mixture of milk and water now how much water must be evaporated in the mixture then Water could be remain 12% in mixture \n" ); document.write( "
Algebra.Com's Answer #723983 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
?
\n" ); document.write( "------------------------------------------------------------------------
\n" ); document.write( "water is 20% the mixture of milk and water now how much water must be evaporated in the mixture then Water could be remain 12% in mixture
\n" ); document.write( "------------------------------------------------------------------------
\n" ); document.write( "?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"Milk\", 80%;
\n" ); document.write( "After evaporation of some water, \"milk\" 88%\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "p, original amount of milk-water mixture
\n" ); document.write( "x, water to remove\r
\n" ); document.write( "\n" ); document.write( "\"%280.8p%29%2F%28p-x%29=0.88\"\r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"0.8p=0.88%28p-x%29\"
\n" ); document.write( "\"0.8p=0.88p-0.88x\"
\n" ); document.write( "\"-0.08p=-0.88x\"
\n" ); document.write( "\"x=%280.08%2F0.88%29p\"
\n" ); document.write( "\"x=8%2F88=1%2F11\"
\n" ); document.write( "\"x=1%2F11\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If start with 1 unit of the milk-and-water mixture, evaporate \"1%2F11\" unit of water from it, to obtain your \"12%\" water result.
\n" ); document.write( "
\n" );