document.write( "Question 1108782: The total amount of money that jim nancy and colin had was $310. Nancy had 3/5 of the amount jim had. Jim gave 2/5 of his money to nancy. Then she gave half of the amount she had to colin. If colin had 4 times as much money as nancy, how much did jim have at first.\r
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Algebra.Com's Answer #723958 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
As I understand this, not totally sure this is right
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\n" ); document.write( " The total amount of money that jim nancy and colin had was $310.
\n" ); document.write( "j + n + c = 310
\n" ); document.write( " Nancy had 3/5 of the amount jim had.
\n" ); document.write( "n = .6j
\n" ); document.write( " Jim gave 2/5 of his money to nancy.
\n" ); document.write( ".4j + n = n's amt then
\n" ); document.write( "replace n with .6j
\n" ); document.write( ".4j + .6j = j is amt n has now and .6j is amt j has now
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\n" ); document.write( " Then she gave half of the amount she had to colin.
\n" ); document.write( ".5j remains with n and .5j + c = colin's amt
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\n" ); document.write( " If colin has 4 times as much money as nancy now,
\n" ); document.write( ".5j + c = 4(.5j)
\n" ); document.write( "c = 2j - .5j
\n" ); document.write( "c = 1.5j
\n" ); document.write( " how much did jim have at first.
\n" ); document.write( "Replace c with 1.5j and .6j for n in the first equation
\n" ); document.write( "j + .6j + 1.5j = 310
\n" ); document.write( "3.1j = 310
\n" ); document.write( "j = $100 amt Jim had a first
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\n" ); document.write( "Please let me know if I am right in this. ankor@att.net\r
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