document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1108855>Question 1108855</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the values of x and y in abcd. ab=2y, bc=y+3 ,CD =5x-1 ,da =2x +4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #723955 by </B><A HREF=/tutors/aboutme.mpl?userid=masinde1><B>masinde1(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=masinde1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=masinde1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=723955\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Draw the trapezium in system as the line ab=cd ,then line bc=da<BR>\n" );
document.write( "    Then since ab=2y,bc=y+3,cd=5x-1,da=2x+4<BR>\n" );
document.write( "          Recall, ab=cd<BR>\n" );
document.write( "                  bc=da<BR>\n" );
document.write( "That is:    2y=5x-1....eqn (i)<BR>\n" );
document.write( "            y+3=2x+4...eqn (ii)<BR>\n" );
document.write( "         <BR>\n" );
document.write( "                  2y-5x=-1...(i)<BR>\n" );
document.write( "                  y-2x=1....(ii)<BR>\n" );
document.write( "  By substitution method..2y=-1+5x. => y=(-1+5x)/2<BR>\n" );
document.write( "      Then substitute the value of y in eqn (ii) <BR>\n" );
document.write( "                 (-1+5x)/2-2x=1. => (-1+5x)-4x=2<BR>\n" );
document.write( "                     -1+5x-4x=2<BR>\n" );
document.write( "                      -1+x=2<BR>\n" );
document.write( "                   X=2+1. => 3<BR>\n" );
document.write( "   Use eqn (ii) to find y ..y-2x=1..y=1+2*3 =>7 therefore. X=3. and y=7 </SPAN>\n" );
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