document.write( "Question 1108906: Scores on a certain test are normally distributed with a variance of 22. A researcher wishes to estimate the mean score achieved by all adults on the test. \r
\n" ); document.write( "\n" ); document.write( "Find the sample size needed to assure with 95% confidence that the sample mean will not differ from the population mean by more than 2 units.
\n" ); document.write( "

Algebra.Com's Answer #723937 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Scores on a certain test are normally distributed with a variance of 22. A researcher wishes to estimate the mean score achieved by all adults on the test.
\n" ); document.write( "Find the sample size needed to assure with 95% confidence that the sample mean will not differ from the population mean by more than 2 units.
\n" ); document.write( "--------
\n" ); document.write( "Since ME = z*s/sqrt(n), n = [z*s/ME]^2
\n" ); document.write( "---------------------------
\n" ); document.write( "Ans: n = [1.96*22/2]^2 = 21.56 ~ 22 when rounded up
\n" ); document.write( "------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "-----------
\n" ); document.write( "
\n" );