document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=99527>Question 99527</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3y+4Help please! :-)\r<BR>\n" );
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document.write( "1.  measure of angle 1 is (3y+4) degrees, measure of angle 2 is (6x+20) degrees, and measure of angle 3 is (3x+y+3) degrees. Solve for x and y, then find the real measure of angle 2. Hint: angles 1 and 3 are vertical angles.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72389 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72389\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3y+4=3x+y+3<BR>\n" );
document.write( "3y+4+6x+20=180<BR>\n" );
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document.write( "rearange:<BR>\n" );
document.write( "subtract 3x and y and 4 from each side: -3x+2y=-1<BR>\n" );
document.write( "subtract 24 from each side: 6x+3y=156 <BR>\n" );
document.write( "multiply 2 times the 1st equation:<BR>\n" );
document.write( "-6x+4y=-2<BR>\n" );
document.write( "6x+3y=156<BR>\n" );
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document.write( "===7y=154<BR>\n" );
document.write( "y=22 Ans.<BR>\n" );
document.write( "replace y with 22 in the 2nd: 6x+66=156<BR>\n" );
document.write( "6x=90<BR>\n" );
document.write( "x=15 Ans.<BR>\n" );
document.write( "angle 2 = 6x+20= 90+20= 110 Ans.<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "angle 1=3y+4=66+4=70<BR>\n" );
document.write( "angle 3=3x+y+3=45+22+3=70<BR>\n" );
document.write( "Ed </SPAN>\n" );
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