document.write( "Question 1108796: Ten years ago, Patty's mother was five times her age. Now, Patty is three sevenths of her mother's age. In five years, Patty will be half of her mother's age. How old will she be when she is half her mother's age? \n" ); document.write( "
Algebra.Com's Answer #723874 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! m = the mother's age now \n" ); document.write( "p = patti's age now \n" ); document.write( ": \n" ); document.write( "Ten years ago, Patty's mother was five times her age. \n" ); document.write( "m - 10 = 5(p-10) \n" ); document.write( "m - 10 = 5p - 50 \n" ); document.write( "m = 5p - 50 + 10 \n" ); document.write( "m = 5p - 40 \n" ); document.write( " Now, Patty is three sevenths of her mother's age. \n" ); document.write( "p = \n" ); document.write( " In five years, Patty will be half of her mother's age. \n" ); document.write( "p + 5 = \n" ); document.write( "multiply 2 to get rid of the fraction \n" ); document.write( "2(p + 5) = m + 5 \n" ); document.write( "2p + 10 = m + 5 \n" ); document.write( "2p = m + 5 - 10 \n" ); document.write( "2p = m - 5 \n" ); document.write( "replace m with (5p - 40) \n" ); document.write( "2p = (5p-40) - 5 \n" ); document.write( "2p = 5p - 45 \n" ); document.write( "2p - 5p = -45 \n" ); document.write( "-3p = -45 \n" ); document.write( "p = -45/-3 \n" ); document.write( "p = +15 yrs is Patti's age \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( "m = 15 * \n" ); document.write( "m = 35 yrs is mom's age \n" ); document.write( ": \n" ); document.write( " How old will she be when she is half her mother's age? \n" ); document.write( "\"In five years, Patty will be half of her mother's age.\" therefore \n" ); document.write( "15 + 5 = 20 yrs old when half mom's age \n" ); document.write( ": \n" ); document.write( "we can confirm this because mom's age 35 + 5 = 40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |