document.write( "Question 1108845: Let n be a three digit number and let m be the number obtained by reversing the order of the digits in n. Suppose that m does not equal n and that n+m and n-m are both divisible by 7. Find all such pairs n and m.\r
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document.write( "I have found
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document.write( "168 and 861
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document.write( "259 and 952\r
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document.write( "Are there any more? \n" );
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Algebra.Com's Answer #723872 by KMST(5328)![]() ![]() You can put this solution on YOUR website! There are no other solutions. My proof is below. \n" ); document.write( "The kids at artofproblemsolving would read it and laugh. \n" ); document.write( "They would probably say that it was obvious based on the Ruszcyk theorem, \n" ); document.write( "or some such thing. \n" ); document.write( "(I just made that theorem up, but they probably have a few modular arithmetic theorems). \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Let the numbers be made of the digits \n" ); document.write( " \n" ); document.write( "To have \n" ); document.write( "and to have \n" ); document.write( " \n" ); document.write( "For any two numbers x and y, \n" ); document.write( "if x-y and x+7 are both multiples of 7, \n" ); document.write( "x and y are both multiples of 7, \n" ); document.write( "and vice versa. \n" ); document.write( "So, m and n must be multiples of 7. \n" ); document.write( "For \n" ); document.write( " \n" ); document.write( "Similarly, for \n" ); document.write( " \n" ); document.write( "If \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "which means \n" ); document.write( " \n" ); document.write( "For \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "With \n" ); document.write( "and then for \n" ); document.write( "it must be \n" ); document.write( "So one solution is \n" ); document.write( " \n" ); document.write( "With \n" ); document.write( "and then for \n" ); document.write( "it must be \n" ); document.write( "So the other solution is |