document.write( "Question 1108845: Let n be a three digit number and let m be the number obtained by reversing the order of the digits in n. Suppose that m does not equal n and that n+m and n-m are both divisible by 7. Find all such pairs n and m.\r
\n" ); document.write( "\n" ); document.write( "I have found
\n" ); document.write( "168 and 861
\n" ); document.write( "259 and 952\r
\n" ); document.write( "\n" ); document.write( "Are there any more?
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Algebra.Com's Answer #723870 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
No, I wrote a short basic program when you submitted it before and it spit out the two pairs that you have there. I did not submit a solution because I could not come up with logical way to find them on paper. All I could find is the difference in the reversed number. Reversed 3 digit numbers, as you no doubt know, are multiples of 99, the difference here will be 7*99 = 693. That is far as I got with it. Not much help just information. ankor@att.net \n" ); document.write( "
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