document.write( "Question 1108783: The denominator of a fraction is 12 more than its numerator. If the numerator is increased by 6 and the denominator is decreased by 5, the result is 7/8. Find the original fraction \n" ); document.write( "
Algebra.Com's Answer #723837 by ankor@dixie-net.com(22740)\"\" \"About 
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The denominator of a fraction is 12 more than its numerator.
\n" ); document.write( "\"n%2F%28%28n%2B12%29%29\"
\n" ); document.write( "If the numerator is increased by 6 and the denominator is decreased by 5, the result is 7/8.
\n" ); document.write( "\"%28%28n%2B6%29%29%2F%28%28n%2B12-5%29%29\" = \"7%2F8\"
\n" ); document.write( ":
\n" ); document.write( "\"%28%28n%2B6%29%29%2F%28%28n%2B7%29%29\" = \"7%2F8\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "8(n+6) = 7(n+7)
\n" ); document.write( "8n + 48 = 7n + 49
\n" ); document.write( "8n - 7n = 49 - 48
\n" ); document.write( "n = 1 is the numerator
\n" ); document.write( "then
\n" ); document.write( "1 + 12 = 13 is the denominator
\n" ); document.write( "then
\n" ); document.write( " \"1%2F13\" is the original fraction
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\n" ); document.write( "Check the solution in the statement
\n" ); document.write( "\"If the numerator is increased by 6 and the denominator is decreased by 5, the result is 7/8.\"
\n" ); document.write( "\"%281%2B6%29%2F%2813-5%29\" = \"7%2F8\"\r
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