document.write( "Question 99481: a van leaves a store at 2:00 going 35 miles an hour
\n" ); document.write( "a car leaves the same store at 2:45 going 50 miles an hour
\n" ); document.write( "how long will it take for the car to pass the van \n" ); document.write( "
Algebra.Com's Answer #72373 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
a van leaves a store at 2:00 going 35 miles an hour
\n" ); document.write( "a car leaves the same store at 2:45 going 50 miles an hour
\n" ); document.write( "how long will it take for the car to pass the van
\n" ); document.write( ":
\n" ); document.write( "Since we are dealing in hrs here, change 45 min: 45/60 = .75 hrs
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\n" ); document.write( "Let t = time traveled for car to pass the van
\n" ); document.write( "then
\n" ); document.write( "(t+.75) = time traveled by the van when this happens
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\n" ); document.write( "We know that when the car passes the van, they will have traveled the same distance.
\n" ); document.write( "We can make a simple distance equation from the this fact.
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\n" ); document.write( "Distance = speed * time
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\n" ); document.write( "Car dist = van dist
\n" ); document.write( "50t = 35(t+.75)
\n" ); document.write( ":
\n" ); document.write( "50t = 35t + 26.25
\n" ); document.write( ":
\n" ); document.write( "50t - 35t = 26.25
\n" ); document.write( ":
\n" ); document.write( "15t = 26.25
\n" ); document.write( ":
\n" ); document.write( "t = 26.25/15
\n" ); document.write( ":
\n" ); document.write( "t = 1.75 hrs, or 1 hr 45 min, for the car to pass the van
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "WE can check our solution by seeing if both vehicles have traveled the same distance.
\n" ); document.write( "50(1.75) = 87.5 mi
\n" ); document.write( "35(1.75+.75) =
\n" ); document.write( "35(2.5) = 87.5 also confirms our solution
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\n" ); document.write( "How about this? Did it make sense to you? \n" ); document.write( "
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