document.write( "Question 1108679: A couple has four children. Let E be the event that the couple has at least two sons, and F the event that the couple has exactly two daughters. Find the intersection and union of two events \n" ); document.write( "

Algebra.Com's Answer #723706 by math_helper(2461) $\"\"$ $\"About$

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Here are all the possible outcomes for having 4 children, sons(S) and daughters(D):
\n" ); document.write( "

\r\n" );
document.write( "SSSS+       DSSS+\r\n" );
document.write( "SSSD+       DSSD*+           \r\n" );
document.write( "SSDS+       DSDS*+\r\n" );
document.write( "SSDD*+      DSDD\r\n" );
document.write( "SDSS+       DDSS*+\r\n" );
document.write( "SDSD*+      DDSD\r\n" );
document.write( "SDDS*+      DDDS\r\n" );
document.write( "SDDD        DDDD\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "The starred * items show which entries have exactly two daughters
\n" ); document.write( "The entries with + indicate cases where they have two or more sons\r
\n" ); document.write( "\n" ); document.write( "Hence the intersection is the 6 entries with *+ \n" ); document.write( "

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