document.write( "Question 1108661: Box contains 78 coins. Only dimes and nickels. Total amount in box $5.90. How many dimes and how many nickels are in box? \n" ); document.write( "
Algebra.Com's Answer #723668 by addingup(3677) You can put this solution on YOUR website! d + n = 78 subtract n from both sides \n" ); document.write( "d = 78 - n \n" ); document.write( "0.10d + 0.05n = 5.90 substitute for d: \n" ); document.write( "0.10(78 - n) + 0.05n = 5.90 \n" ); document.write( "7.80 - 0.10n + 0.05n = 5.90 \n" ); document.write( "7.80 - 0.05n = 5.90 \n" ); document.write( "- 0.05n = - 1.90 \n" ); document.write( "n = 38 so there are 38 nickels and 78 - 38 = 40 dimes \n" ); document.write( "----------------------- \n" ); document.write( "Check: \n" ); document.write( "38(0.05) + 40(0.10) = 5.90 Correct \n" ); document.write( " |