document.write( "Question 1108651: I am trying to find a solution to a problem for my 7th grader that has me confused. \r
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document.write( "I have a rectangle.
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document.write( "The long side \"length\" is 3x + 4 and the short side \"width\" is x - 2. \r
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document.write( "The perimeter is 20. \r
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document.write( "I have to figure the value of x. \r
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document.write( "I came up with the value of 2 for x.\r
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document.write( "If that is correct that the rectangle would have 2 sides of 10cm
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document.write( "And 2 sides of 0. Please help. \r
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document.write( " _____3x_+4_________
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document.write( " |x -2
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document.write( "P = 20. Solve for x \r
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Algebra.Com's Answer #723665 by addingup(3677) You can put this solution on YOUR website! Perimeter = 2L + 2W. Agreed? If so: \n" ); document.write( "2(3x + 4) + 2(x - 2) = 20 \n" ); document.write( "Distributive Law of multiplication: \n" ); document.write( "6x + 8 + 2x - 4 = 20 \n" ); document.write( "Group similar: \n" ); document.write( "6x + 2x + 8 - 4 = 20 \n" ); document.write( "8x + 4 = 20 \n" ); document.write( "Subtract 4, both sides: \n" ); document.write( "8x = 16 \n" ); document.write( "x = 2 \n" ); document.write( "------------------------------- \n" ); document.write( "Check: \n" ); document.write( "2(3 * 2 + 4) + 2(2 - 2) = 20 \n" ); document.write( "2(6 + 4) + 4 - 4 = 20 \n" ); document.write( "12 + 8 + 4 - 4 = 20 \n" ); document.write( "20 + 0 = 20 Correct \n" ); document.write( " \n" ); document.write( " |