document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=99497>Question 99497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help! PLEASE! I can't seem to figure these out!\r<BR>\n" );
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document.write( "1.  One number is 6 more than another number. The sum of the sumbers is one more than 3 times their difference.  What are the numbers?\r<BR>\n" );
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document.write( "2.  In a small rowboat, it took Alice 6 hours to go 6 miles upstream, but she was able to return to her starting point in only 45 minutes.  Assuming her rowing speed was constant, what was the speed of the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72366 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72366\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. One number is 6 more than another number. The sum of the sumbers is one more than 3 times their difference. What are the numbers?<BR>\n" );
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document.write( "Let one of the numbers be \"x\"; the other number is \"x+6\"<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "x + x+6 = 3(x+6-x) + 1<BR>\n" );
document.write( "2x+6 = 18+1<BR>\n" );
document.write( "x = 13/2<BR>\n" );
document.write( "x = 6.5 (one of the numbers)<BR>\n" );
document.write( "x+6 = 12.5 (the other number)<BR>\n" );
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document.write( "2. In a small rowboat, it took Alice 6 hours to go 6 miles upstream, but she was able to return to her starting point in only 45 minutes. Assuming her rowing speed was constant, what was the speed of the current?<BR>\n" );
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document.write( "Upstream DATA:<BR>\n" );
document.write( "distance=6 miles ; time = 6 hrs; rate = d/t= 1 mph<BR>\n" );
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document.write( "Downstream DATA:<BR>\n" );
document.write( "distance = 6 miles ; time = (3/4) hr ; rate = d/t = 6/(3/4) = 8 mph<BR>\n" );
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document.write( "Let speed in quiet water be \"b\"; let speed of stream be \"s\"<BR>\n" );
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document.write( "EQUATIONS:<BR>\n" );
document.write( "b+s = 8 mph<BR>\n" );
document.write( "b-s = 1 mph<BR>\n" );
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document.write( "Add to get:<BR>\n" );
document.write( "2b = 9mph<BR>\n" );
document.write( "b = 4.5 mph (speed of boat in quiet water)<BR>\n" );
document.write( "Substitue to solve for \"s\":<BR>\n" );
document.write( "4.5+s = 8<BR>\n" );
document.write( "s = 3.5 mph (speed of the stream)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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