document.write( "Question 1108536: A cube of side length s sits inside a sphere of radius r so that the vertices of the cube sit on the sphere. Find the ratio r : s. \n" ); document.write( "
Algebra.Com's Answer #723610 by KMST(5328)\"\" \"About 
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Let us pretend that this sketch really looks like the cube
\n" ); document.write( "The seven visible vertices are labeled A through G.
\n" ); document.write( "Vertex H is in back. In the attempted perspective view,
\n" ); document.write( "H is directly behind D, and directly below E.
\n" ); document.write( "\"s=AB=BC=CD=DG=FG=AE\" is the length of a side of the cube.
\n" ); document.write( "\"AE=sqrt%28s%5E2%2Bs%5E2%29=sqrt%282%29s\" is the length of the diagonal of a cube face.
\n" ); document.write( "A cross-section (cutting through A, F, G, and D, would look like this
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\n" ); document.write( " is the length of the diagonal of the cube,
\n" ); document.write( "the longest possible distance between two points of the cube.
\n" ); document.write( "For the cube to fit in the sphere, that has to be the diameter of the sphere.
\n" ); document.write( "So, \"2r=sqrt%283%29s\" --> \"highlight%28r%2Fs=sqrt%283%29%2F2%29\" .
\n" ); document.write( "The ratio r:s is \"highlight%28sqrt%283%29%2F2%29\" (about 0.866).
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