document.write( "Question 1108596: Simplify\r
\n" ); document.write( "\n" ); document.write( "cos^2 x sec^2 x -cos^2 x
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Algebra.Com's Answer #723592 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
This is cos^2 x(sec^2 x -1)
\n" ); document.write( "but sec^2 x-1 is (1/cos^2 x)-(cos^2 x/cos^2 x) or (1-cos^2x)/cos^2 x) or
\n" ); document.write( "sin^2 x/cos^2 x\r
\n" ); document.write( "\n" ); document.write( "Therefor, this is cos^2 x* sin^2 x/cos^2 x=sin^2 x
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