document.write( "Question 1108567: What is the fifth term of a geometric sequence whose first term is 32,768 and common ratio is one fourth? \n" ); document.write( "
Algebra.Com's Answer #723546 by Theo(13342)\"\" \"About 
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if the first term is 32768 and the common ratio is 1/4, then each succeeding term in the sequence is 1/4 * the value of the preceding term.\r
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\n" ); document.write( "\n" ); document.write( "if you let the first term be x, then the second term is 1/4 * x and the 3d term is 1/4 * that and the 4th term is 1/4 * that and the 5th term is 1/4 * that.\r
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\n" ); document.write( "\n" ); document.write( "you get x * 1/4 * 1/4 * 1/4 * 1/4 which is equal to x * (1/4) ^ 4.\r
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\n" ); document.write( "\n" ); document.write( "so the first term in the geometric sequence is 32768 * (1/4) ^ 4.\r
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\n" ); document.write( "\n" ); document.write( "that makes it equal top 128.\r
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\n" ); document.write( "\n" ); document.write( "the general formula says An = A1 * r ^ (n-1)\r
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\n" ); document.write( "\n" ); document.write( "A1 = 32768
\n" ); document.write( "r = 1/4
\n" ); document.write( "n = 5\r
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\n" ); document.write( "\n" ); document.write( "using this formula, you get A5 = 32768 * (1/4) ^ 4.\r
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\n" ); document.write( "\n" ); document.write( "if you work by multiplying each succeeding term by 1/4, you get:\r
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\n" ); document.write( "\n" ); document.write( "A1 = 32768
\n" ); document.write( "A2 = A1 * 1/4 = 8192
\n" ); document.write( "A3 = A2 * 1/4 = 2048
\n" ); document.write( "A4 = A3 * 1/4 = 512
\n" ); document.write( "A5 = A4 * 1/4 = 128\r
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