document.write( "Question 1108562: Six students are lining up for flag ceremony. If three persons insist on standing next to each other, how many ways can the six students arrange themselves? \n" ); document.write( "

Algebra.Com's Answer #723545 by josmiceli(19441) $\"\"$ $\"About$

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The 3 that must be together can arrange
\n" ); document.write( "themselves 6 different ways:
\n" ); document.write( "a b c
\n" ); document.write( "a c b
\n" ); document.write( "b a c
\n" ); document.write( "b c a
\n" ); document.write( "c a b
\n" ); document.write( "c b a
\n" ); document.write( "P( 3,1 ) = 3! / 1!
\n" ); document.write( "P( 3,1 ) = 6
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\n" ); document.write( "Each one of these 6 possible groupings can
\n" ); document.write( "fit into the arrangements of the other 3 students:
\n" ); document.write( "( think of the 3 that must be together as one
\n" ); document.write( "student that 6 different identities )
\n" ); document.write( " $\"+6%2AP%28+4%2C1+%29+\"$
\n" ); document.write( " $\"+6%2A%28+4%21%2F1%21+%29+\"$
\n" ); document.write( " $\"+6%2A4%2A3%2A2%2A1+=+144+\"$
\n" ); document.write( "144 different ways
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\n" ); document.write( "Definitely get a 2nd opinion if needed
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