document.write( "Question 99457: Could you tell me if I have this correct. \r
\n" ); document.write( "\n" ); document.write( "During rush hour, Bill can drive 15 miles using the side roads in the same time that it takes to travel 10 miles on the freeway. If Bill's rate on the side roads in 8 mi/h faster than his rate on the freeway, find his rate on the side roads. \r
\n" ); document.write( "\n" ); document.write( "Is the answer 24? Thank you.
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Algebra.Com's Answer #72352 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
I THINK THAT YOU ARE RIGHT ON!!!!!!!!!!!!!!!!\r
\n" ); document.write( "\n" ); document.write( "distance(d)=rate(r) times time(t) or d=rt; t=d/r and r=d/t
\n" ); document.write( "Let r=his rate on the side roads\r
\n" ); document.write( "\n" ); document.write( "Then r-8=his rate on the freeway\r
\n" ); document.write( "\n" ); document.write( "Time to drive 15 mi using the side roads=15/r\r
\n" ); document.write( "\n" ); document.write( "Time to drive 10 mi using the freeway=10/(r-8)\r
\n" ); document.write( "\n" ); document.write( "Now we are told that these two times are the same. So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "15/r=10/(r-8) multiply both sides by r(r-8)\r
\n" ); document.write( "\n" ); document.write( "15(r-8)=10r get rid of parens\r
\n" ); document.write( "\n" ); document.write( "15r-120=10r subtract 15r from both sides\r
\n" ); document.write( "\n" ); document.write( "15r-15r-120=10r-15r collect like terms\r
\n" ); document.write( "\n" ); document.write( "-120=-5r divide both sides by -5\r
\n" ); document.write( "\n" ); document.write( "r=24 mph------------------------rate on side roads\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "15/24=10/16
\n" ); document.write( "5/8=5/8
\n" ); document.write( "Hope this helps---ptaylor\r
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