document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1108518>Question 1108518</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the denominator of a fraction is 6 more than the numerator. If the numerator is decreased by 3 and the denominator is increased by 3, the value of the resulting fraction is 1/7. What is the original fraction? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #723507 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=723507\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x/(x+6)<BR>\n" );
document.write( "(x-3)/(x+3) = 1/7<BR>\n" );
document.write( "7(x-3) = x+3<BR>\n" );
document.write( "7x-21 = x+3<BR>\n" );
document.write( "6x = 24<BR>\n" );
document.write( "x = 4\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );