document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1108482>Question 1108482</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following system of linear equations using the substitution method:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1%2F4%29x+%2B+%283%2F2%29y+=+11 ALIGN=MIDDLE  ALT=\"%28-1%2F4%29x+%2B+%283%2F2%29y+=+11\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1%2F8%29x+%2B+%281%2F3%29y+=+3 ALIGN=MIDDLE  ALT=\"%28-1%2F8%29x+%2B+%281%2F3%29y+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Express answer as an ordered pair.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #723481 by </B><A HREF=/tutors/aboutme.mpl?userid=TeachMath><B>TeachMath(96)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TeachMath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=723481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> – ¼x + (3/2)y = 11<BR>\n" );
document.write( "(– 1/8)x + (1/3)y = 3\r<BR>\n" );
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document.write( "Multiply eq 1 by - 4 to get: x - 6y = - 44____x = 6y - 44<BR>\n" );
document.write( "Multiply eq 2 by LCD, 24 to get: - 3x + 8y = 72<BR>\n" );
document.write( "Then substitute 6y - 44 for x in the equation: - 3x + 8y = 72<BR>\n" );
document.write( "This should give you a y-value of 6<BR>\n" );
document.write( "Substitute 6 for y in any of the 2 original equations to get an x-value of - 8. </SPAN>\n" );
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