document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=99445>Question 99445</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write an equation of the line that passes through the point (/3,5) and has a slope of (-2/3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72343 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72343\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> IF THESE POINTS ARE(3,5)&(-2,3) THEN THE EQUATION IS<BR>\n" );
document.write( "5=-2/3*3+b<BR>\n" );
document.write( "5=-2+b<BR>\n" );
document.write( "b=5+2<BR>\n" );
document.write( "b=7<BR>\n" );
document.write( "THEREFORE THE EQUTAION IS:<BR>\n" );
document.write( "Y=-2X/3+7 <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );