document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1108414>Question 1108414</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write as a trigonometry ratio of A, with the correct sign attached:\r<BR>\n" );
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document.write( "cosec (-A)\r<BR>\n" );
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document.write( "cosec (180+A)\r<BR>\n" );
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document.write( "cosec (180-A) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #723429 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=723429\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write as a trigonometry ratio of A, with the correct sign attached:\r<BR>\n" );
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document.write( "cosec (-A)\r<BR>\n" );
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document.write( "cosec (180+A)\r<BR>\n" );
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document.write( "cosec (180-A)<BR>\n" );
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document.write( "The signs of the csc match those of the sine, since csc = 1/sin<BR>\n" );
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document.write( "cosec (-A) =  -csc\r<BR>\n" );
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document.write( "cosec (180+A) = -csc\r<BR>\n" );
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document.write( "cosec (180-A) = csc<BR>\n" );
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