document.write( "Question 1108402: In a town of 900 people, 400 are employed of which 300 are men,and 100 are women, if there are 600 men in d town,wat is d probability of pikin a person being a woman or unemployed \n" ); document.write( "
Algebra.Com's Answer #723413 by ikleyn(52909) You can put this solution on YOUR website! . \n" ); document.write( " \r\n" );
document.write( "1. The set {woman OR unemployed} is equal to the set {women + unemployed man}.\r\n" );
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document.write( " The last set is the union of two disjoint sets, which is easier to analyse.\r\n" );
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document.write( "2. From the condition, there are 300 = 900 - 600 women in the town.\r\n" );
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document.write( " The number of unemployed man is 600 - 300 = 300.\r\n" );
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document.write( "3. So, the set {women + unemployed man} consists of 300 + 300 = 600 persons.\r\n" );
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document.write( " Now the probability under the question = (women + unemploeyed man)/(total population) = \r\n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |