document.write( "Question 1108402: In a town of 900 people, 400 are employed of which 300 are men,and 100 are women, if there are 600 men in d town,wat is d probability of pikin a person being a woman or unemployed \n" ); document.write( "
Algebra.Com's Answer #723413 by ikleyn(52909)\"\" \"About 
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document.write( "1.  The set  {woman OR unemployed}  is equal to the set  {women + unemployed man}.\r\n" );
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document.write( "    The last set is the union of two disjoint sets, which is easier to analyse.\r\n" );
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document.write( "2.  From the condition, there are 300 = 900 - 600 women in the town.\r\n" );
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document.write( "    The number of unemployed man is 600 - 300 = 300.\r\n" );
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document.write( "3.  So, the set  {women + unemployed man}  consists of 300 + 300 = 600 persons.\r\n" );
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document.write( "    Now the probability under the question = (women + unemploeyed man)/(total population) = \"600%2F900\" = \"2%2F3\".\r\n" );
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