document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1108392>Question 1108392</A>: <I><SPAN STYLE=\"word-break: break-all;\"> David is X years old and Martin is 3 years older if the sum of their ages is 37 write an equation based on this information <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #723396 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=723396\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> David's current age = x<BR>\n" );
document.write( "Martin's current age = x+3\r<BR>\n" );
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document.write( "The sum of their ages has us add up the two expressions (x and x+3) so we end up with (x)+(x+3) = x+x+3 = 2x+3\r<BR>\n" );
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document.write( "We're told that \"the sum of their ages is 37\", so set 2x+3 equal to 37 to get the answer 2x+3 = 37 </SPAN>\n" );
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